Re: chemistry questions

There was a request for explanation of #6 on the practice review, so
here it is:

#6) The key is that ALL the strong acid's H+'s will tie up anions
(base ions). When HCl is added to the flouride solution, the new H+
ions will react with the free flouride ions and turn them into HF.
1. Count the # of flouride ions in 25.0 mL of solution
2. Subtract the # of H+ ions added
3. Divide the new number by the new volume (30.0 mL)